![]() ![]() C o m p o s i t e R − v a l u e = 19.76 ° F f t 2 h B T U So the answer is 19.76 degrees F, foot squared, hour over BTUs. When you add all these three layers up, you get a total R-value of 19.76. And we have a third layer of a drywall and this drywall has an R-value of 0.45, half inch drywall. So we are using 5 inches so 5 times 3.7 would be 18.50. And this fiberglass thickness is given as 5” and its R-value is given as 3.7 per inch. And we have a second layer of fiberglass. The first layer is wood siding which is outside, obviously, and its R-value is given as 0.81, whatever the thickness might be of that wood siding. Here we have, again a wall made up of three different layers. What is the R-value of a wall that is made up of wood siding (R= 0.81), 5” of fiberglass (R=3.70 per inch), and a layer of. If you would like to find out more about Spra圜ork, please contact our team on 01484 442420 or email we can put you in touch with a local approved applicator for a quote.Lesson 7b, Screen 8: Composite Wall R-Values Example 11 It does so without compromising on your space and without damaging the environment. Used as an interior wall coating, Spra圜ork has been found to reduce heating bills by as much as 15%. ![]() And it actually makes walls more resistant to damp, with a water-repellent layer that damp and mould can’t form on. It’s suitable for any wall surface on the inside of a building. In stark contrast, Spra圜ork’s final coating is just 8mm thick. Remove your existing plaster, add insulative materials, then replaster – which is both time consuming and costly, while still being pretty bulky. ![]()
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